Voltages
ID: 08A, 092. 09A, 0A2, 0AA, 0B2, 0BA, 0C2, 0CA, 0D2, 0DA (11 sheets, 11 IDs)
B1 \ Minimum voltage (low 8 bits)
B2 / Minimum voltage (high 8 bits), scaled 8192
B3 \ Maximum voltage (low 8 bits)
B4 / Maximum voltage (high 8 bits), scale 8192
B5 \ Average voltage (low 8 bits)
B6 | Average voltage (mid 8 bits)
B7 / Average voltage (high 8 bits), scale 9*8192 (9 bricks per sheet)
B8 Minimum brick# (low 4 bits), maximum brick# (high 4 bits)
The B7 factor is my best guess, looking at data from just one car. With 9 bricks per sheet, it seems obvious this is 9*8192, and that seems to match the log data the best.
For example, I have '08A 67 81 90 81 0f 8e 04 04'. This is:
* 08A Sheet #1 (of 11). Presumably ((ID - 08A)/8)+1 is sheet number.
* 67 81 33127/8192 = 4.0438v
* 90 81 33168/8192 = 4.0488v
* 0f 8e 04 298511/(9*8192) = 4.0488v
* 04 Minimum brick #4, maximum brick #0 (both relative to sheet #1)
So, another way of looking at the average voltage is sheet voltage (36.4393v in the above example).